90+17x=3x^2

Solution for 90+17x=3x^2 equation:

90+17x=3x^2

We move all terms to the left:

90+17x-(3x^2)=0

determiningTheFunctionDomain
-3x^2+17x+90=0

a = -3; b = 17; c = +90;
Δ = b2-4ac
Δ = 172-4·(-3)·90
Δ = 1369
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1369}=37$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(17)-37}{2*-3}=\frac{-54}{-6}
=+9
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(17)+37}{2*-3}=\frac{20}{-6}
=-3+1/3
$